1300=-16t^2+1700

Solution for 1300=-16t^2+1700 equation:

1300=-16t^2+1700

We move all terms to the left:

1300-(-16t^2+1700)=0

We get rid of parentheses

16t^2-1700+1300=0

We add all the numbers together, and all the variables

16t^2-400=0

a = 16; b = 0; c = -400;
Δ = b2-4ac
Δ = 02-4·16·(-400)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*16}=\frac{-160}{32}
=-5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*16}=\frac{160}{32}
=5
$